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To express \((x + 3)^2\) as a trinomial, you need to expand it using the formula for the square of a binomial, which is:

\[
(a + b)^2 = a^2 + 2ab + b^2
\]

Here, \(a = x\) and \(b = 3\). Let's apply this:

\[
(x + 3)^2 = x^2 + 2(x)(3) + 3^2
\]

Simplifying:

\[
x^2 + 6x + 9
\]

So, the trinomial form of \((x + 3)^2\) is:

\[
x^2 + 6x + 9
\]

Would you like further details or have any other questions?

Here are 5 related questions for practice:
1. What is the result of \((x - 4)^2\)?
2. How would you expand \((2x + 5)^2\)?
3. Can you expand \((x + 7)^2\) using the same method?
4. What is the simplified form of \((3x + 2)^2\)?
5. How does the middle term change when squaring a binomial with a negative second term?

**Tip:** Always remember the middle term comes from doubling the product of the two terms in the binomial!

Express (x + 3)^2 as a trinomial in standard form.

Learn how to expand the binomial (x + 3)^2 using algebraic techniques to express it as a trinomial. Understand the formula for squaring a binomial and see the detailed solution for x^2 + 6x + 9. Ideal for students in Grades 7-9.

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