The expression $(x - 3)^2$ can be expanded using the formula for the square of a binomial:

$(a - b)^2 = a^2 - 2ab + b^2$

Applying this formula:

$(x - 3)^2 = x^2 - 2(x)(3) + 3^2$

$(x - 3)^2 = x^2 - 6x + 9$

Final Answer:

$(x - 3)^2 = x^2 - 6x + 9$

Would you like further explanations, or do you have additional questions?

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Related Questions:

1. How do you expand $(x + a)^2$?
2. Can you simplify $(x - 3)^3$?
3. What are the steps for factoring $x^2 - 6x + 9$?
4. How do you solve $(x - 3)^2 = 16$?
5. What is the geometric interpretation of $(x - 3)^2$?

Tip:

Always remember that $(a - b)^2$ results in a trinomial with positive squares of both terms and a negative middle term (if $b$ is positive).