Math Problem Statement

(2x + 3)²

Solution

To simplify the expression (2x+3)2(2x + 3)^2, you can expand it using the binomial formula:

(a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2

In your case:

  • a=2xa = 2x
  • b=3b = 3

Now apply the formula:

(2x+3)2=(2x)2+2(2x)(3)+32(2x + 3)^2 = (2x)^2 + 2(2x)(3) + 3^2

Simplify each term:

(2x)2=4x2(2x)^2 = 4x^2

2(2x)(3)=12x2(2x)(3) = 12x

32=93^2 = 9

So, the expanded form is:

(2x+3)2=4x2+12x+9(2x + 3)^2 = 4x^2 + 12x + 9

Would you like any further details or have any questions about this solution?


Here are five related questions:

  1. How would you expand (3x4)2(3x - 4)^2?
  2. What is the expanded form of (x+5)2(x + 5)^2?
  3. How do you factor the quadratic expression 4x2+12x+94x^2 + 12x + 9?
  4. Can you solve the equation (2x+3)2=0(2x + 3)^2 = 0 for xx?
  5. What is the general form of a binomial square expansion?

Tip: Memorizing the binomial expansion formula can greatly speed up your work with polynomials!

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Math Problem Analysis

Mathematical Concepts

Algebra
Binomial theorem

Formulas

Binomial expansion formula

Theorems

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Suitable Grade Level

Grades 7-9