Math Problem Statement

Solve for the value of a,a.(3a+2)° (2a-2)

Solution

To solve the expression for the value of aa, we first need to correctly interpret the given expression.

It appears the expression is:

a(3a+2)(2a2)a \cdot (3a + 2)^\circ (2a - 2)

But degrees (°) typically indicate an angle or power. If you meant a power or degree symbol unintentionally, could you clarify?

Assuming you meant the multiplication of the terms instead of a degree symbol, the expression could be interpreted as:

a(3a+2)(2a2)a \cdot (3a + 2) \cdot (2a - 2)

Now let's solve it step by step:

Step 1: Expand the terms.

a(3a+2)(2a2)a \cdot (3a + 2) \cdot (2a - 2)

First, expand the two binomials:

(3a+2)(2a2)=3a2a+3a(2)+22a+2(2)(3a + 2)(2a - 2) = 3a \cdot 2a + 3a \cdot (-2) + 2 \cdot 2a + 2 \cdot (-2)

=6a26a+4a4= 6a^2 - 6a + 4a - 4

=6a22a4= 6a^2 - 2a - 4

Step 2: Multiply by aa.

Now, multiply the result by aa:

a(6a22a4)=a6a2+a(2a)+a(4)a \cdot (6a^2 - 2a - 4) = a \cdot 6a^2 + a \cdot (-2a) + a \cdot (-4)

=6a32a24a= 6a^3 - 2a^2 - 4a

Thus, the final expanded expression is:

6a32a24a6a^3 - 2a^2 - 4a

If you need to solve this equation for specific values of aa, please provide more context, such as an equation set equal to 0 or another number.


Would you like more details, or do you have any further questions? Here are some related problems to consider:

  1. Expand and simplify: (x+1)(x5)(2x+3)(x + 1)(x - 5)(2x + 3).
  2. Factor 6a32a24a6a^3 - 2a^2 - 4a.
  3. Solve for aa if 6a32a24a=06a^3 - 2a^2 - 4a = 0.
  4. Simplify a(a1)(a+2)a(a - 1)(a + 2).
  5. Find the value of aa if a(2a1)=12a(2a - 1) = 12.

Tip: When dealing with expressions involving multiple terms, always start by expanding and simplifying before trying to solve.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Polynomial Expansion
Multiplication of Polynomials

Formulas

Polynomial multiplication: (ax + b)(cx + d) = acx^2 + (ad + bc)x + bd

Theorems

Distributive Property

Suitable Grade Level

Grades 8-10