Math Problem Statement

Determine the following values from the graph of the function f(x). a. lim x→2^- f(x) = ?, b. lim x→2^+ f(x) = ?, c. lim x→2 f(x) = ?, d. f(2) = ?

Solution

Let's analyze the graph and address the limit questions one by one.

a. limx2f(x)\lim_{x \to 2^-} f(x)

  • As xx approaches 2 from the left (denoted by x2x \to 2^-), we can see from the graph that the function approaches 44.
  • Answer: 4

b. limx2+f(x)\lim_{x \to 2^+} f(x)

  • As xx approaches 2 from the right (denoted by x2+x \to 2^+), the graph shows that the function goes to infinity. The open circle at x=2x = 2 suggests a discontinuity, and the graph increases rapidly upwards.
  • Answer: \infty (already checked)

c. limx2f(x)\lim_{x \to 2} f(x)

  • The two-sided limit requires both the left-hand and right-hand limits to be equal. Since the left-hand limit approaches 4 and the right-hand limit approaches infinity, the limit does not exist.
  • Answer: DNE

d. f(2)f(2)

  • From the graph, at x=2x = 2, there is an open circle at f(2)=4f(2) = 4, and a solid point is located at f(2)=3f(2) = 3. The value of the function at this point is 3 (due to the filled dot at (2,3)(2, 3)).
  • Answer: 3

Would you like further clarification on any part of this explanation? Here are some related questions to consider:

  1. What is the significance of open and closed circles on a graph in terms of limits and function values?
  2. How do we distinguish between left-hand and right-hand limits on a graph?
  3. Why does a discontinuity at a point affect the two-sided limit?
  4. Can you explain when a limit approaches infinity and when it does not exist?
  5. How does the function's behavior near discontinuities help in evaluating limits?

Tip: When evaluating two-sided limits, always ensure that both one-sided limits are equal, otherwise the two-sided limit does not exist.

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Math Problem Analysis

Mathematical Concepts

Limits
Discontinuities
Piecewise Functions

Formulas

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Theorems

Limit Laws
One-Sided Limits
Discontinuities and Continuity

Suitable Grade Level

Grades 11-12 (Calculus)