Math Problem Statement
Evaluate the Boolean expressions based on the given variable declarations.
Solution
The image provides a table of expressions and answers, with the following variables declared:
boolean expr1 = 23 >= 12
, which evaluates totrue
since 23 is greater than or equal to 12.boolean expr2 = 53 <= 45
, which evaluates tofalse
since 53 is not less than or equal to 45.int grade = 80
int score = 49
double celsius = 32.22
Now, let's evaluate each expression:
a. expr1 && expr2 || expr1 ^ expr2
expr1 && expr2
:true && false
=false
expr1 ^ expr2
:true ^ false
=true
(XOR)false || true
=true
Answer: true
b. (!expr2 != expr2) && expr2 || 15 != 3 * 5
!expr2
:!false
=true
!expr2 != expr2
:true != false
=true
(true) && expr2
:true && false
=false
15 != 3 * 5
:15 != 15
=false
false || false
=false
Answer: false
c. 9 != -9 ^ 7 < 9 - 2 && (!expr1 || expr2)
9 != -9
:true
7 < 9 - 2
:7 < 7
=false
9 != -9 ^ false
:true ^ false
=true
!expr1
:!true
=false
!expr1 || expr2
:false || false
=false
true && false
=false
Answer: false
d. expr1 ^ !expr2 || !true && 23 > 3 * 2
expr1 ^ !expr2
:true ^ true
=false
!true
:false
23 > 3 * 2
:23 > 6
=true
false || false && true
:false || false
=false
Answer: false
e. expr1 || 34 <= 12 * 3 && (26 > 2 * 12.5)
expr1
:true
34 <= 12 * 3
:34 <= 36
=true
26 > 2 * 12.5
:26 > 25
=true
true && true
:true
true || true
=true
Answer: true
f. !(expr1 ^ !true) || (expr2 && !false)
!true
:false
expr1 ^ false
:true ^ false
=true
!(true)
:false
!false
:true
expr2 && true
:false && true
=false
false || false
=false
Answer: false
g. (celsius >= 26) && (celsius <= 37) ^ true
celsius >= 26
:32.22 >= 26
=true
celsius <= 37
:32.22 <= 37
=true
true ^ true
:false
true && false
=false
Answer: false
h. (score > 50) && (score < 100) || !(true)
score > 50
:49 > 50
=false
score < 100
:49 < 100
=true
false && true
:false
!(true)
:false
false || false
=false
Answer: false
i. (grade >= 75) && (expr1 || grade < 75)
grade >= 75
:80 >= 75
=true
grade < 75
:80 < 75
=false
expr1 || false
:true || false
=true
true && true
=true
Answer: true
j. 14 * 2 > 28 && expr1 || expr2 ^ (12 > 13)
14 * 2 > 28
:28 > 28
=false
expr1
:true
false && true
:false
12 > 13
:false
expr2 ^ false
:false ^ false
=false
false || false
=false
Answer: false
Would you like more details on any of these steps?
5 Follow-up Questions:
- How does XOR (
^
) work in Boolean logic? - Can you explain the difference between logical AND (
&&
) and logical OR (||
)? - Why does the expression
expr1 || true
always evaluate totrue
? - In expression (g), why does the result change when using XOR (
^
) withtrue
? - What is the role of parentheses in expressions to determine the order of operations?
Tip:
When solving complex Boolean expressions, remember that operations inside parentheses are evaluated first, and the precedence order follows this: !
(NOT), ^
(XOR), &&
(AND), then ||
(OR).
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Math Problem Analysis
Mathematical Concepts
Boolean Logic
Conditional Statements
Logical Operators
Formulas
Logical AND (&&), Logical OR (||), NOT (!), XOR (^)
Theorems
Order of Operations in Boolean Expressions
Truth Tables
Suitable Grade Level
Grades 10-12