Math Problem Statement

  1. 2x + 11 2. (2z + y) -5 3. (Y + z ) - x x is 21 y is 22 z is 20

Solution

Let's evaluate each expression step by step, substituting the given values x=21x = 21, y=22y = 22, and z=20z = 20.

  1. For 2x+112x + 11: 2(21)+11=42+11=532(21) + 11 = 42 + 11 = 53

  2. For (2z+y)5(2z + y) - 5: (2(20)+22)5=(40+22)5=625=57(2(20) + 22) - 5 = (40 + 22) - 5 = 62 - 5 = 57

  3. For (Y+z)x(Y + z) - x: (22+20)21=4221=21(22 + 20) - 21 = 42 - 21 = 21

Results:

  1. 2x+11=532x + 11 = 53
  2. (2z+y)5=57(2z + y) - 5 = 57
  3. (Y+z)x=21(Y + z) - x = 21

If you want more details on any step or have questions, let me know!

Additional Questions:

  1. How do you evaluate expressions with variables in algebra?
  2. What are the properties of addition and multiplication used here?
  3. How would the results change if xx, yy, or zz were different?
  4. Can you provide an example of a similar problem?
  5. What strategies do you find helpful for solving equations with multiple variables?

Tip:

When substituting values in expressions, always double-check the arithmetic to avoid simple mistakes.

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Math Problem Analysis

Mathematical Concepts

Algebra
Expressions
Substitution

Formulas

2x + 11
(2z + y) - 5
(Y + z) - x

Theorems

-

Suitable Grade Level

Grades 7-9