1. 2x + 11 2. (2z + y) -5 3. (Y + z ) - x x is 21 y is 22 z is 20

Let's evaluate each expression step by step, substituting the given values \( x = 21 \), \( y = 22 \), and \( z = 20 \).

1. **For \( 2x + 11 \)**:
   \[
   2(21) + 11 = 42 + 11 = 53
   \]

2. **For \( (2z + y) - 5 \)**:
   \[
   (2(20) + 22) - 5 = (40 + 22) - 5 = 62 - 5 = 57
   \]

3. **For \( (Y + z) - x \)**:
   \[
   (22 + 20) - 21 = 42 - 21 = 21
   \]

### Results:
1. \( 2x + 11 = 53 \)
2. \( (2z + y) - 5 = 57 \)
3. \( (Y + z) - x = 21 \)

If you want more details on any step or have questions, let me know!

### Additional Questions:
1. How do you evaluate expressions with variables in algebra?
2. What are the properties of addition and multiplication used here?
3. How would the results change if \( x \), \( y \), or \( z \) were different?
4. Can you provide an example of a similar problem?
5. What strategies do you find helpful for solving equations with multiple variables?

### Tip:
When substituting values in expressions, always double-check the arithmetic to avoid simple mistakes.

Explore the step-by-step evaluation of the algebraic expressions 2x + 11, (2z + y) - 5, and (Y + z) - x using x = 21, y = 22, and z = 20. Ideal for students in Grades 7-9 learning about algebra and substitution.

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