Math Problem Statement

Evaluate the following integral in cylindrical coordinates.

ModifyingAbove ModifyingBelow Integral from nothing to nothing With 3 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With 2 StartRoot 2 EndRoot width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot 16 minus x squared EndRoot width x e Superscript negative x squared minus y squared Baseline dy font size decreased by 4 dx font size decreased by 4 dz3∫ 022∫0 16−x2∫xe−x2−y2dy dx dz

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Part 1

ModifyingAbove ModifyingBelow Integral from nothing to nothing With 3 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With 2 StartRoot 2 EndRoot width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot 16 minus x squared EndRoot width x e Superscript negative x squared minus y squared Baseline dy font size decreased by 4 dx font size decreased by 4 dz3∫ 022∫0 16−x2∫xe−x2−y2dy dx dzequals=enter your response here

​(Simplify your answer. Type an exact​ answer, using

piπ

as​ needed.)

Solution

We are asked to evaluate the following triple integral in cylindrical coordinates:

0302x16x2ex2y2dydxdz\int_{0}^{3} \int_{0}^{\sqrt{2}} \int_{x}^{\sqrt{16 - x^2}} e^{-x^2 - y^2} \, dy \, dx \, dz

Step 1: Express the integral in cylindrical coordinates

In cylindrical coordinates, we have the following relationships:

  • x=rcosθx = r \cos \theta
  • y=rsinθy = r \sin \theta
  • z=zz = z (unchanged)
  • The area element dxdydx\,dy becomes rdrdθr \, dr \, d\theta due to the Jacobian in cylindrical coordinates.

Moreover, x2+y2=r2x^2 + y^2 = r^2, and thus the exponential term ex2y2e^{-x^2 - y^2} transforms to er2e^{-r^2}.

Step 2: Boundaries for cylindrical coordinates

We need to convert the limits of integration:

  • zz runs from 0 to 3.
  • The xyxy-region is circular, as x2+y216x^2 + y^2 \leq 16, so rr ranges from 0 to 4 (since 16=4\sqrt{16} = 4).
  • The angle θ\theta will range from 0 to 2π2\pi for a full circular region.

Thus, the integral becomes:

030402πrer2dθdrdz\int_0^3 \int_0^{4} \int_0^{2\pi} r e^{-r^2} \, d\theta \, dr \, dz

Step 3: Evaluate the integral over θ\theta

The θ\theta-integral is straightforward:

02πdθ=2π\int_0^{2\pi} d\theta = 2\pi

This simplifies the integral to:

2π0304rer2drdz2\pi \int_0^3 \int_0^4 r e^{-r^2} \, dr \, dz

Step 4: Evaluate the radial integral

We now focus on the radial part:

04rer2dr\int_0^4 r e^{-r^2} \, dr

This integral can be solved using substitution. Let u=r2u = r^2, so du=2rdrdu = 2r \, dr, or du2=rdr\frac{du}{2} = r \, dr. The limits for uu will go from 0 to 1616 as rr ranges from 0 to 4.

Thus, the radial integral becomes:

12016eudu\frac{1}{2} \int_0^{16} e^{-u} \, du

The integral of eue^{-u} is simply eu-e^{-u}, so:

12[eu]016=12(e16+e0)=12(1e16)\frac{1}{2} \left[ -e^{-u} \right]_0^{16} = \frac{1}{2} \left( -e^{-16} + e^0 \right) = \frac{1}{2} \left( 1 - e^{-16} \right)

Step 5: Putting it all together

Now, the remaining integral is:

2π0312(1e16)dz2\pi \int_0^3 \frac{1}{2} \left( 1 - e^{-16} \right) \, dz

This simplifies to:

π(1e16)03dz=π(1e16)3\pi \left( 1 - e^{-16} \right) \int_0^3 dz = \pi \left( 1 - e^{-16} \right) \cdot 3

Thus, the final answer is:

3π(1e16)\boxed{3\pi \left( 1 - e^{-16} \right)}

Would you like more details on any part of this solution? Here are some related questions to practice:

  1. How do you compute integrals involving cylindrical coordinates?
  2. What are common transformations for triple integrals into cylindrical coordinates?
  3. Why does the Jacobian in cylindrical coordinates introduce an extra rr?
  4. How do you handle substitution in exponential integrals like rer2dr\int r e^{-r^2} \, dr?
  5. What is the significance of boundary conditions when converting to cylindrical coordinates?

Tip: Always check the region of integration carefully when switching to cylindrical or spherical coordinates—it can greatly simplify the integral!

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Math Problem Analysis

Mathematical Concepts

Triple Integrals
Cylindrical Coordinates
Exponential Functions
Coordinate Transformations

Formulas

x = r * cos(θ)
y = r * sin(θ)
Integral: ∫ e^(-r^2) * r * dr
Volume element in cylindrical coordinates: r * dr * dθ * dz

Theorems

Jacobian determinant for cylindrical coordinates
Exponential integral substitution

Suitable Grade Level

University Level (Advanced Calculus/Multivariable Calculus)