Math Problem Statement
Evaluate the following integral in cylindrical coordinates.
ModifyingAbove ModifyingBelow Integral from nothing to nothing With 3 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With 2 StartRoot 2 EndRoot width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot 16 minus x squared EndRoot width x e Superscript negative x squared minus y squared Baseline dy font size decreased by 4 dx font size decreased by 4 dz3∫ 022∫0 16−x2∫xe−x2−y2dy dx dz
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Part 1
ModifyingAbove ModifyingBelow Integral from nothing to nothing With 3 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With 2 StartRoot 2 EndRoot width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot 16 minus x squared EndRoot width x e Superscript negative x squared minus y squared Baseline dy font size decreased by 4 dx font size decreased by 4 dz3∫ 022∫0 16−x2∫xe−x2−y2dy dx dzequals=enter your response here
(Simplify your answer. Type an exact answer, using
piπ
as needed.)
Solution
We are asked to evaluate the following triple integral in cylindrical coordinates:
Step 1: Express the integral in cylindrical coordinates
In cylindrical coordinates, we have the following relationships:
- (unchanged)
- The area element becomes due to the Jacobian in cylindrical coordinates.
Moreover, , and thus the exponential term transforms to .
Step 2: Boundaries for cylindrical coordinates
We need to convert the limits of integration:
- runs from 0 to 3.
- The -region is circular, as , so ranges from 0 to 4 (since ).
- The angle will range from 0 to for a full circular region.
Thus, the integral becomes:
Step 3: Evaluate the integral over
The -integral is straightforward:
This simplifies the integral to:
Step 4: Evaluate the radial integral
We now focus on the radial part:
This integral can be solved using substitution. Let , so , or . The limits for will go from 0 to as ranges from 0 to 4.
Thus, the radial integral becomes:
The integral of is simply , so:
Step 5: Putting it all together
Now, the remaining integral is:
This simplifies to:
Thus, the final answer is:
Would you like more details on any part of this solution? Here are some related questions to practice:
- How do you compute integrals involving cylindrical coordinates?
- What are common transformations for triple integrals into cylindrical coordinates?
- Why does the Jacobian in cylindrical coordinates introduce an extra ?
- How do you handle substitution in exponential integrals like ?
- What is the significance of boundary conditions when converting to cylindrical coordinates?
Tip: Always check the region of integration carefully when switching to cylindrical or spherical coordinates—it can greatly simplify the integral!
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Math Problem Analysis
Mathematical Concepts
Triple Integrals
Cylindrical Coordinates
Exponential Functions
Coordinate Transformations
Formulas
x = r * cos(θ)
y = r * sin(θ)
Integral: ∫ e^(-r^2) * r * dr
Volume element in cylindrical coordinates: r * dr * dθ * dz
Theorems
Jacobian determinant for cylindrical coordinates
Exponential integral substitution
Suitable Grade Level
University Level (Advanced Calculus/Multivariable Calculus)
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