Math Problem Statement
Solution
The image shows a mathematical expression related to surface integrals. It involves a vector field , where , , and are constants. The task is to evaluate the surface integral of this vector field over the surface of a unit sphere.
This type of question involves applying the Divergence Theorem to simplify the calculation.
Approach:
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The Divergence Theorem states that the surface integral of a vector field over a closed surface is equal to the volume integral of the divergence of the vector field inside the region bounded by the surface.
Mathematically: Where is the closed surface (in this case, the surface of a sphere), and is the volume inside the sphere.
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Compute the Divergence of : Since , , and are constants:
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Volume Integral: The volume integral becomes: Since is a constant, the integral is: The volume of a unit sphere is .
Thus, the surface integral is:
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Result: Therefore, the final result of the surface integral is:
Summary:
The integral , where , evaluates to , with being the surface of the unit sphere.
Would you like further details or clarifications on any part of the solution? Here are some follow-up questions:
- How is the Divergence Theorem derived?
- How do we compute the surface integral for non-constant vector fields?
- Can the Divergence Theorem be used for non-spherical surfaces?
- How is the divergence of a vector field computed in general?
- What is the relationship between surface integrals and flux?
Tip: When dealing with vector fields and surface integrals, always consider using the Divergence Theorem to simplify the calculations if the surface is closed and the region is easily defined.
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Math Problem Analysis
Mathematical Concepts
Vector Calculus
Surface Integrals
Divergence
Formulas
Divergence Theorem: ∫∫ F · dS = ∫∫∫ (∇ · F) dV
Divergence of F: ∇ · F = ∂(ax)/∂x + ∂(by)/∂y + ∂(cz)/∂z
Volume of a sphere: (4/3)πr³
Theorems
Divergence Theorem
Suitable Grade Level
College Level
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