f(1) = StartFraction 5 x plus 7 Over 8 x minus 3 EndFraction
5x+7
8x−3

It looks like you want to evaluate the function \( f(x) = \frac{5x + 7}{8x - 3} \) at \( x = 1 \). Let’s substitute \( x = 1 \) into the function and simplify.

### Step 1: Substitute \( x = 1 \) into the function
\[
f(1) = \frac{5(1) + 7}{8(1) - 3}
\]

### Step 2: Simplify the numerator and the denominator
\[
f(1) = \frac{5 + 7}{8 - 3} = \frac{12}{5}
\]

Thus, \( f(1) = \frac{12}{5} \).

Would you like further details or explanations on how I arrived at this solution?

Here are five related questions:
1. How would you evaluate \( f(2) \) using the same function \( f(x) = \frac{5x + 7}{8x - 3} \)?
2. What happens to the function as \( x \to \infty \)?
3. Can you find the vertical asymptote of the function \( f(x) \)?
4. What is the domain of the function \( f(x) = \frac{5x + 7}{8x - 3} \)?
5. How would you find the inverse of this rational function?

**Tip**: When dealing with rational functions, always check for undefined values in the denominator to avoid dividing by zero.

f(1) = StartFraction 5x + 7 Over 8x - 3 EndFraction

Learn how to evaluate the rational function f(x) = (5x + 7) / (8x - 3) at x = 1. This step-by-step guide simplifies the function to find f(1) = 12/5. Explore key algebraic concepts like rational functions and function evaluation, suitable for students in Grades 9-11.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation