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The given function is:

\[
f(x) = \frac{2}{x - 3}
\]

We are asked to find \( f(5) \), which means substituting \( x = 5 \) into the function.

\[
f(5) = \frac{2}{5 - 3} = \frac{2}{2} = 1
\]

Thus, \( f(5) = 1 \).

Would you like further clarification or have any questions?

Here are five related questions:
1. What happens to \( f(x) \) as \( x \) approaches 3?
2. Can you find \( f(0) \) for the same function?
3. How would the function change if it was \( f(x) = \frac{3}{x - 4} \)?
4. What is the domain of the function \( f(x) = \frac{2}{x - 3} \)?
5. How does \( f(x) \) behave as \( x \) approaches infinity?

**Tip:** When evaluating functions, always ensure that the denominator does not result in zero to avoid undefined expressions.

This problem involves evaluating the function f(x) = 2 / (x - 3) at x = 5. Learn how to substitute the value of x and simplify the result to find that f(5) = 1. This problem introduces basic function evaluation, suitable for students in Grades 9-10.

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