To evaluate $-\left(\frac{2}{5}\right)^2$:

1. Square the fraction $\frac{2}{5}$: $\left(\frac{2}{5}\right)^2 = \frac{2^2}{5^2} = \frac{4}{25}$

2. Apply the negative sign: $-\left(\frac{4}{25}\right) = -\frac{4}{25}$

So, $-\left(\frac{2}{5}\right)^2 = -\frac{4}{25}$.

Would you like a more detailed explanation or have any questions?

Here are 5 related questions:

1. What is the square of $\left(\frac{3}{7}\right)$?
2. How do you handle negative exponents in fractions?
3. What is $-\left(\frac{4}{9}\right)^3$?
4. How does squaring a fraction affect its numerator and denominator?
5. What is $\left(\frac{-2}{5}\right)^2$?

Tip: When squaring a negative number, always remember that the result is positive unless the negative is outside the parentheses.