Math Problem Statement

(b) limx!1 (x + 1)e x

Solution

To evaluate the limit

limx1(x+1)ex\lim_{{x \to 1}} (x + 1)e^x

we proceed by direct substitution, as the function (x+1)ex(x + 1)e^x is continuous at x=1x = 1.

  1. Substitute x=1x = 1 into (x+1)ex(x + 1)e^x: (1+1)e1=2e(1 + 1)e^1 = 2e

Thus, the answer is:

limx1(x+1)ex=2e\lim_{{x \to 1}} (x + 1)e^x = 2e

Would you like further details or have any questions?

Here are some related questions you might find helpful:

  1. How would you evaluate limx0xex\lim_{{x \to 0}} x \cdot e^x?
  2. What steps are used to evaluate limits involving exponential functions?
  3. How does the continuity of exponential functions affect limit evaluation?
  4. What is the general behavior of exe^x as xx approaches different values?
  5. How would you solve limxxex\lim_{{x \to \infty}} \frac{x}{e^x}?

Tip: When solving limits with exponential functions, direct substitution is often effective if the function is continuous at the point of interest.

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Math Problem Analysis

Mathematical Concepts

Limits
Exponential Functions
Continuity

Formulas

lim x→c f(x) = f(c) if f(x) is continuous at x = c

Theorems

Limit Continuity Theorem

Suitable Grade Level

Grade 12 or College Calculus