To find $h(2)$, substitute $t = 2$ into the given function $h(t) = -t^2 - 2t - 4$:

$h(2) = -(2)^2 - 2(2) - 4$

Step-by-step solution:

1. Compute $(2)^2 = 4$, so: $h(2) = -4 - 2(2) - 4$

2. Compute $2(2) = 4$, so: $h(2) = -4 - 4 - 4$

3. Combine all terms: $h(2) = -12$

Final Answer:

$h(2) = -12$

Would you like additional details or have any questions? 😊

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Related Questions:

1. How would you find $h(-2)$ for the same function?
2. What is the vertex of the parabola represented by $h(t) = -t^2 - 2t - 4$?
3. Can you factorize $h(t)$ into a product of two expressions?
4. What is the axis of symmetry for $h(t)$?
5. How does the graph of $h(t)$ compare to $g(t) = t^2 + 2t + 4$?

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Tip:

When solving for a function value, always simplify each term carefully to avoid errors.