Given h, of, x, equals, minus, 2, x, plus, 1h(x)=−2x+1, find h, of, 4h(4).

To find \( h(4) \), substitute \( x = 4 \) into the function \( h(x) = -2x + 1 \):

\[
h(4) = -2(4) + 1
\]

\[
h(4) = -8 + 1
\]

\[
h(4) = -7
\]

So, \( h(4) = -7 \).

Would you like to explore further steps or details? Here are 5 related questions to consider:

1. What is the domain and range of the function \( h(x) = -2x + 1 \)?
2. How does the graph of \( h(x) \) look like in a coordinate system?
3. Can we determine the slope and y-intercept of \( h(x) \)?
4. How do we find \( h(a) \) for any value of \( a \)?
5. How would \( h(x) \) change if the function were \( h(x) = -2x - 1 \)?

**Tip:** When solving linear equations, always identify the slope and intercept to help understand the function visually.

Understand how to evaluate h(4) for the linear function h(x) = -2x + 1. This problem demonstrates key algebraic skills, including substitution and basic operations, suitable for students in Grades 6-8.

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