Let's solve the two problems shown in the image.

Problem 3:

The function given is $h(n) = -2n + 4$. We need to find $h(4)$.

Solution: Substitute $n = 4$ into the function:

$h(4) = -2(4) + 4 = -8 + 4 = -4$

So, $h(4) = -4$.

Problem 4:

The function given is $h(t) = -2 \cdot 5 - t - 1$. We need to find $h(-2)$.

Solution: First, simplify the function. It looks like there may be some confusion with the expression, but assuming it is:

$h(t) = -2 \times 5 - t - 1$

Simplifying further:

$h(t) = -10 - t - 1 = -t - 11$

Now substitute $t = -2$ into the function:

$h(-2) = -(-2) - 11 = 2 - 11 = -9$

So, $h(-2) = -9$.

Would you like any more details, or do you have any questions? Here are some related questions you might find interesting:

1. What would $h(n)$ be if $n = -3$ in problem 3?
2. Can you rewrite the function in problem 4 in a different form?
3. What is the general method for evaluating a function at a specific value?
4. How would the results change if the coefficient of $t$ in problem 4 were positive?
5. How can you check your answers to these types of problems?

Tip: Always double-check the original function to ensure you're simplifying it correctly before substituting values.