https://file.aiquickdraw.com/mathbot/file/17254438720894hllk3ut.jpg

Let's solve the two problems shown in the image.

### Problem 3:
The function given is \( h(n) = -2n + 4 \). We need to find \( h(4) \).

**Solution:**
Substitute \( n = 4 \) into the function:

\[
h(4) = -2(4) + 4 = -8 + 4 = -4
\]

So, \( h(4) = -4 \).

### Problem 4:
The function given is \( h(t) = -2 \cdot 5 - t - 1 \). We need to find \( h(-2) \).

**Solution:**
First, simplify the function. It looks like there may be some confusion with the expression, but assuming it is:

\[
h(t) = -2 \times 5 - t - 1
\]

Simplifying further:

\[
h(t) = -10 - t - 1 = -t - 11
\]

Now substitute \( t = -2 \) into the function:

\[
h(-2) = -(-2) - 11 = 2 - 11 = -9
\]

So, \( h(-2) = -9 \).

Would you like any more details, or do you have any questions? Here are some related questions you might find interesting:

1. What would \( h(n) \) be if \( n = -3 \) in problem 3?
2. Can you rewrite the function in problem 4 in a different form?
3. What is the general method for evaluating a function at a specific value?
4. How would the results change if the coefficient of \( t \) in problem 4 were positive?
5. How can you check your answers to these types of problems?

**Tip:** Always double-check the original function to ensure you're simplifying it correctly before substituting values.

Find h(4) for h(n) = -2n + 4 and find h(-2) for h(t) = -2 * 5 - t - 1

Learn how to evaluate linear functions at specific values by solving h(4) for h(n) = -2n + 4 and h(-2) for h(t) = -2 * 5 - t - 1. This problem is perfect for students in Grades 7-9, covering core algebraic concepts.

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