To solve for $f(x+1)$, given that $f(x) = 3x - 5$:

1. Substitute $x+1$ for $x$ in the expression for $f(x)$: $f(x+1) = 3(x+1) - 5$

2. Expand and simplify: $f(x+1) = 3x + 3 - 5 = 3x - 2$

So, $f(x+1) = 3x - 2$.

Would you like more details on this process, or do you have any questions?

Here are some related questions:

1. How do we evaluate $f(x + a)$ for a general value of $a$?
2. What is the significance of function transformations in this context?
3. How would $f(x) = 3x - 5$ change if we modified the coefficient of $x$?
4. Can you find $f(x-1)$ using the same method?
5. How does this function behave as $x$ approaches infinity?

Tip: When substituting in functions, carefully replace every instance of $x$ with the new expression to avoid errors.