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The given linear function is \( f(x) = 3x - 1 \). We are asked to find the values of \( f(0) \), \( f(1) \), and \( f(2) \).

Let's evaluate these:

1. **For \( f(0) \):**
   \[
   f(0) = 3(0) - 1 = 0 - 1 = -1
   \]

2. **For \( f(1) \):**
   \[
   f(1) = 3(1) - 1 = 3 - 1 = 2
   \]

3. **For \( f(2) \):**
   \[
   f(2) = 3(2) - 1 = 6 - 1 = 5
   \]

### Results:
- \( f(0) = -1 \)
- \( f(1) = 2 \)
- \( f(2) = 5 \)

Would you like further details or explanations on any of these steps?

Here are five follow-up questions to expand on this:
1. What does the slope of this linear function represent geometrically?
2. How would the function change if the slope were doubled?
3. What is the y-intercept of this function, and how can it be interpreted?
4. How can we use this function to find the equation of a line parallel to it?
5. What would happen to the function if the constant term (-1) were increased?

**Tip:** For any linear function \( f(x) = mx + b \), \( m \) represents the slope, which dictates how steep the line is, and \( b \) represents the y-intercept, showing where the line crosses the y-axis.

Consider the linear function f(x) = 3x - 1. Find f(0), f(1), f(2).

Learn how to solve the linear function f(x) = 3x - 1 by evaluating it at different values of x. This detailed example covers key algebraic concepts for students in Grades 6-8.

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