Math Problem Statement

Given g(x) = 2^x + 1, evaluate the following. (a) g(3)

(b) g(2)

(c) g(-2)

Solution

Given the function g(x)=2x+1g(x) = 2^x + 1, we can evaluate it at the specified values:

(a) g(3)g(3)

g(3)=23+1=8+1=9g(3) = 2^3 + 1 = 8 + 1 = 9

(b) g(2)g(2)

g(2)=22+1=4+1=5g(2) = 2^2 + 1 = 4 + 1 = 5

(c) g(2)g(-2)

g(2)=22+1=122+1=14+1=1.25g(-2) = 2^{-2} + 1 = \frac{1}{2^2} + 1 = \frac{1}{4} + 1 = 1.25

Thus, the results are:

  • g(3)=9g(3) = 9
  • g(2)=5g(2) = 5
  • g(2)=1.25g(-2) = 1.25

Would you like more details or have any questions?

Here are 5 related questions for further exploration:

  1. What is the general behavior of g(x)g(x) as xx increases or decreases?
  2. How would you calculate g(x)g(x) for fractional values of xx?
  3. What is the inverse of g(x)g(x), if it exists?
  4. How does g(x)g(x) compare to other exponential functions, like g(x)=3x+1g(x) = 3^x + 1?
  5. Can you graph g(x)=2x+1g(x) = 2^x + 1 and describe its shape?

Tip: For negative exponents, 2x=12x2^{-x} = \frac{1}{2^x}, which makes the function decrease as xx becomes more negative.

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Math Problem Analysis

Mathematical Concepts

Exponential Functions
Function Evaluation

Formulas

g(x) = 2^x + 1

Theorems

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Suitable Grade Level

Grades 9-11