Math Problem Statement

Evaluate the function. Round answers to four decimal places, if necessary. f(x) = 2.4(4)^(-x+1) + 1.2 for f(-2.2).

Solution

Let's break down the given function to evaluate f(2.2)f(-2.2).

The function is: f(x)=2.4(4)x+1+1.2f(x) = 2.4(4)^{-x+1} + 1.2 You are asked to find f(2.2)f(-2.2).

Step 1: Substitute x=2.2x = -2.2 into the function

f(2.2)=2.4(4)(2.2)+1+1.2f(-2.2) = 2.4(4)^{-(-2.2) + 1} + 1.2

Simplify the exponent: (2.2)+1=2.2+1=3.2-(-2.2) + 1 = 2.2 + 1 = 3.2

So now we have: f(2.2)=2.4(4)3.2+1.2f(-2.2) = 2.4(4)^{3.2} + 1.2

Step 2: Calculate (4)3.2(4)^{3.2}

Using a calculator: 43.285.79394^{3.2} \approx 85.7939

Step 3: Multiply by 2.4

2.4×85.7939205.90542.4 \times 85.7939 \approx 205.9054

Step 4: Add 1.2

f(2.2)=205.9054+1.2=207.1054f(-2.2) = 205.9054 + 1.2 = 207.1054

Final Answer:

f(2.2)207.1054f(-2.2) \approx 207.1054

Would you like more details on any step?

Here are 5 questions to deepen your understanding:

  1. What are the properties of exponents that were used here?
  2. How do we handle negative exponents and negative values for xx?
  3. What would change if the base 4 in the exponent were replaced with a different number?
  4. How does rounding affect the final result in functions like these?
  5. What role does the constant 1.2 play in the overall behavior of the function?

Tip: When working with exponents, pay close attention to negative signs, as they can change the behavior of the function significantly.

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Math Problem Analysis

Mathematical Concepts

Exponents
Function Evaluation
Algebra

Formulas

f(x) = 2.4(4)^(-x+1) + 1.2

Theorems

Exponentiation rules

Suitable Grade Level

Grades 10-12