Let's address the two problems from the image, based on the provided functions:

We are given the following functions:

• $f(x) = \sqrt{x}$
• $g(x) = \frac{x + 1}{x + 2}$
• $h(x) = |x - 1|$

Problem 1: $(f + g)(3)$

To solve $(f + g)(3)$, we first evaluate each function separately at $x = 3$, and then add their results:

1. Evaluate $f(3)$: $f(3) = \sqrt{3}$

2. Evaluate $g(3)$: $g(3) = \frac{3 + 1}{3 + 2} = \frac{4}{5}$

Now, add the two values: $(f + g)(3) = f(3) + g(3) = \sqrt{3} + \frac{4}{5}$ This is the simplified form of $(f + g)(3)$.

Problem 2: $(f \circ h)(-3)$

To solve $(f \circ h)(-3)$, we first compute $h(-3)$, and then use that result as the input for $f$.

1. Evaluate $h(-3)$: $h(-3) = |-3 - 1| = |-4| = 4$

2. Evaluate $f(4)$: $f(4) = \sqrt{4} = 2$

Thus, $(f \circ h)(-3) = f(h(-3)) = 2$.

Would you like further clarification on any part of this? Here are some related questions for practice:

1. What is $(f \cdot g)(2)$?
2. Can you compute $(g \circ h)(1)$?
3. What is the value of $(f + h)(0)$?
4. What happens when you compute $(g \circ f)(4)$?
5. How do you interpret the behavior of $f(x)$ as $x \to 0$?

Tip: When evaluating compositions of functions, work from the inside out, starting with the innermost function and then applying the outer function.