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To evaluate \( f(6) \), we will substitute \( x = 6 \) into the function \( f(x) = 5x - 20 \).

\[
f(6) = 5(6) - 20 = 30 - 20 = 10
\]

Therefore, \( f(6) = 10 \).

Do you need more details or have any questions?

Here are 5 related questions:
1. What would \( f(0) \) be for the function \( f(x) = 5x - 20 \)?
2. How does the function \( f(x) \) behave as \( x \to \infty \)?
3. Can you find \( g(6) \) for \( g(x) = x^2 + 5x - 11 \)?
4. What is the solution to \( f(x) = 0 \)?
5. How would you graph \( f(x) = 5x - 20 \)?

**Tip**: When evaluating functions, always substitute the given value of \( x \) into the equation and simplify carefully.

Evaluate: f(6) for the function f(x) = 5x - 20

Learn how to evaluate the linear function f(x) = 5x - 20 at x = 6. This example involves substituting the value of x into the function and simplifying, an important concept in algebra for students in Grades 6-8.

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