To evaluate $g(x) = 5x + 1$ at $x = -2$, substitute $x = -2$ into the equation:

$g(-2) = 5(-2) + 1$

Simplify:

$g(-2) = -10 + 1 = -9$

Thus, $g(-2) = -9$.

Would you like further explanation or additional details?

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Related Questions:

1. How do we determine the slope and y-intercept from a linear function?
2. What is the general process for evaluating functions at specific points?
3. How can we graph $g(x) = 5x + 1$ on a coordinate plane?
4. How does changing the slope affect the graph of a linear function?
5. What happens if we calculate $g(x)$ for $x = 0$?

Tip:

Always check your substitution carefully to avoid calculation errors, especially when dealing with negatives.