It seems you have uploaded the same image again. The evaluation of the function $f(x) = -2x^3 - 3x^2 + x + 2$ when $x = 0$ remains as follows:

Step-by-Step:

Substitute $x = 0$ into the function:

$f(0) = -2(0)^3 - 3(0)^2 + 0 + 2 = 2$

Therefore, the value of the function when $x = 0$ is 2.

The correct answer is $\boxed{2}$.

If you have any more questions or need clarification, feel free to ask!

Here are 5 related questions for further understanding:

1. What is the value of $f(x)$ when $x = 1$?
2. How would you graph this cubic function?
3. What are the points where the function crosses the x-axis?
4. How does the function behave for large negative values of $x$?
5. What is the second derivative of the function $f(x)$?

Tip: Always verify your substitutions carefully when working with polynomials to avoid small mistakes.