If \[f(x)=-2x^3+3x^2-11x+1\], what is the value of \[f(0)\] ?

To find the value of \( f(0) \) for the function \( f(x) = -2x^3 + 3x^2 - 11x + 1 \), substitute \( x = 0 \) into the function:

\[
f(0) = -2(0)^3 + 3(0)^2 - 11(0) + 1
\]

Simplifying the terms:

\[
f(0) = 0 + 0 + 0 + 1 = 1
\]

Therefore, the value of \( f(0) \) is \( \boxed{1} \).

Would you like more details, or do you have any questions?

Here are 5 related questions:
1. What is \( f(1) \) for the same function?
2. How would you find the roots of \( f(x) = 0 \)?
3. What is the derivative \( f'(x) \) of this function?
4. Can you find the turning points of \( f(x) \)?
5. What is the end behavior of \( f(x) \) as \( x \to \infty \)?

**Tip**: When substituting values into functions, always replace \( x \) with the given number carefully in each term.

If [f(x)=-2x^3+3x^2-11x+1], what is the value of [f(0)]?

Learn how to find the value of f(0) for the polynomial function f(x) = -2x^3 + 3x^2 - 11x + 1 with a step-by-step solution. This problem involves algebraic concepts and polynomial evaluation, suitable for students in Grades 9-11.

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