We are given the function $h(x) = 4x + 3$, and we are asked to find $h(4)$ and then $h(h(4))$.

Step 1: Calculate $h(4)$

We use the function $h(x) = 4x + 3$ to find $h(4)$.

$h(4) = 4(4) + 3 = 16 + 3 = 19$

Step 2: Calculate $h(h(4))$

Now, we know that $h(4) = 19$. We will substitute $x = 19$ into the function to calculate $h(19)$.

$h(19) = 4(19) + 3 = 76 + 3 = 79$

Final Answer

Thus, $h(h(4)) = 79$.

Would you like further details or have any questions?

Here are 5 related questions for further practice:

1. Find $h(h(2))$ if $h(x) = 4x + 3$.
2. If $h(x) = 2x - 5$, what is $h(h(1))$?
3. Find the inverse of the function $h(x) = 4x + 3$.
4. Solve $h(x) = 23$ for $x$ if $h(x) = 4x + 3$.
5. What is the value of $h(x)$ when $x = 0$?

Tip: When working with composite functions, always start by evaluating the innermost function first before proceeding outward.