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The given function is \( h(x) = 4x + 4 \). We need to complete the function table by calculating \( h(x) \) for each given value of \( x \).

### Calculations:
1. **For \( x = -3 \):**
   \[
   h(-3) = 4(-3) + 4 = -12 + 4 = -8
   \]
2. **For \( x = -1 \):**
   \[
   h(-1) = 4(-1) + 4 = -4 + 4 = 0
   \]
3. **For \( x = 0 \):**
   \[
   h(0) = 4(0) + 4 = 0 + 4 = 4
   \]
4. **For \( x = 3 \):**
   \[
   h(3) = 4(3) + 4 = 12 + 4 = 16
   \]
5. **For \( x = 5 \):**
   \[
   h(5) = 4(5) + 4 = 20 + 4 = 24
   \]

### Completed Function Table:
| \( x \) | \( h(x) \) |
|:------:|:----------:|
| -3     | -8         |
| -1     | 0          |
| 0      | 4          |
| 3      | 16         |
| 5      | 24         |

Would you like further details or have any questions?

### Related Questions:
1. How do you determine the slope of a linear function like \( h(x) = 4x + 4 \)?
2. What is the y-intercept of the function \( h(x) = 4x + 4 \)?
3. How do you graph the function \( h(x) = 4x + 4 \) using the table values?
4. What happens to the value of \( h(x) \) as \( x \) increases?
5. How would the function table change if the function was \( h(x) = 4x - 4 \)?

### Tip:
For any linear function of the form \( h(x) = mx + b \), \( m \) represents the slope, indicating how steep the line is, and \( b \) is the y-intercept, showing where the line crosses the y-axis.

The function h is defined by the rule h(x) = 4x + 4. Complete the function table for given x values: -3, -1, 0, 3, 5.

Learn how to complete a function table for the linear function h(x) = 4x + 4. This problem involves evaluating h(x) for values -3, -1, 0, 3, and 5, showcasing how to apply the rule of a linear function. Suitable for students in Grades 6-8.

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