To find $ab^2c$, substitute the given values into the expression:

$a = -3, \, b = -2, \, c = 6$

Step 1: Substitute into the expression

$ab^2c = (-3)(-2)^2(6)$

Step 2: Simplify $b^2$

$(-2)^2 = 4$

Step 3: Multiply the values

$ab^2c = (-3)(4)(6)$

$ab^2c = -12 \cdot 6$

$ab^2c = -72$

Final Answer:

$ab^2c = -72$

Would you like further details or clarifications? Here are 5 related questions to expand your understanding:

1. How would $ab^2c$ change if $b$ were positive?
2. What is the effect of squaring a negative number on the final result?
3. Can you generalize this computation for any values of $a, b,$ and $c$?
4. What if $c$ were zero in this expression—how would the result be affected?
5. How does the order of operations influence the computation in $ab^2c$?

Tip: Always square values before multiplying when dealing with exponents in expressions!