Math Problem Statement

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Skip to Main content Question 1 Question 2 Question 3 Question 4 Question 5 Question 6 Question 7 Question 8 Question content area top Part 1 A​ nation's population​ (to the nearest​ million) was 281 million in 2000 and 310 in 2010. It is projected that the population in 2050 will be 437 million. To construct a logistic​ model, both the growth rate and the carrying capacity must be estimated. There are several ways to estimate these parameters. Use parts​ (a) through​ (f) to use one approach. Question content area bottom Part 1 a. Assume that tequals0 corresponds to 2000 and that the population growth is exponential for the first ten​ years; that​ is, between 2000 and​ 2010, the population is given by Upper P left parenthesis t right parenthesis equals Upper P left parenthesis 0 right parenthesis e Superscript rt. Estimate the growth rate r using this assumption. requals    enter your response here ​(Round to five decimal places as​ needed.) r(Round to five decimal places as needed.)P(t)K(Type an integer or decimal rounded to the nearest hundredth as needed.)The population will reach 95% of the carrying capacity in the year(Type an integer or decimal rounded to the nearest hundredth as needed.)K(Type an integer or decimal rounded to the nearest hundredth as needed.)K(Type an integer or decimal rounded to the nearest hundredth as needed.)Choose the correct response below.r(Round to five decimal places as needed.) Get more help

Solution

To estimate the growth rate rr using the given exponential growth model, we start by using the equation for population growth:

P(t)=P(0)ertP(t) = P(0) e^{rt}

Where:

  • P(t)P(t) is the population at time tt,
  • P(0)P(0) is the initial population at t=0t = 0,
  • rr is the growth rate,
  • tt is the time in years since 2000.

Step 1: Identify the Known Values

  • P(0)=281P(0) = 281 million (population in the year 2000),
  • P(10)=310P(10) = 310 million (population in the year 2010),
  • t=10t = 10 years (since 2010 is 10 years after 2000).

Step 2: Apply the Exponential Growth Equation

We have:

310=281×e10r310 = 281 \times e^{10r}

Step 3: Solve for the Growth Rate rr

First, isolate the exponential term:

310281=e10r\frac{310}{281} = e^{10r}

Next, take the natural logarithm on both sides:

ln(310281)=10r\ln\left(\frac{310}{281}\right) = 10r

Finally, solve for rr:

r=110ln(310281)r = \frac{1}{10} \ln\left(\frac{310}{281}\right)

Let's calculate this value.

The estimated growth rate rr is approximately 0.009820.00982 when rounded to five decimal places.

Would you like any further details on this calculation, or do you have any other questions?

Here are 5 related questions to consider:

  1. How would the population change if the growth rate doubled?
  2. What would be the population in 2020 using the exponential growth model?
  3. How does exponential growth differ from logistic growth?
  4. What are some factors that could cause the growth rate to change over time?
  5. How does the carrying capacity impact the logistic growth model?

Tip: Always check the units when solving exponential growth problems, as they can affect the interpretation of your results.

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Logistic Growth
Population Modeling

Formulas

P(t) = P(0) e^{rt}
r = (1/t) ln(P(t)/P(0))

Theorems

Exponential Growth Model
Logarithmic Properties

Suitable Grade Level

Grades 10-12