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To estimate the percentage of ants in the "smaller" category, we need to determine the number of ants with body lengths of at most 6.5 mm from the histogram. Here’s the step-by-step solution:

1. **Identify Bars for Body Lengths at Most 6.5 mm:** 
   - The histogram shows data from body lengths of 4 mm up to 9 mm.
   - We need to count the bars that represent ants with body lengths of 4 mm, 5 mm, and up to (but not including) 7 mm, which includes the range from 4 mm to 6 mm.

2. **Calculate Total Frequency for 4 mm to 6 mm:**
   - From the histogram:
     - **4 mm bar**: Very low, around 5 ants.
     - **5 mm bar**: About 50 ants.
     - **6 mm bar**: Very low, around 5 ants.
   - Total for smaller ants = 5 + 50 + 5 = 60 ants.

3. **Calculate Percentage:**
   - The total number of ants measured is 300.
   - Percentage of smaller ants = \(\frac{60}{300} \times 100\% = 20\%\).

**Answer: 20% of the ants are in the ‘smaller’ category.**

Would you like more details on this calculation or have any questions?

Here are some related questions:
1. How would the percentage change if we included ants up to 7 mm as "smaller"?
2. What if the histogram included more body length intervals beyond 9 mm?
3. How can histograms help in biological research?
4. Could body length distribution indicate the roles of ants in other species?
5. How do we interpret overlapping intervals on histograms?

**Tip:** When working with histograms, always double-check frequency estimates, especially for intervals close to the category boundaries.

Estimate the percentage of the ants that are in the 'smaller' category, given a histogram showing the frequency distribution of body lengths (in mm) of 300 green ants. Smaller ants are defined as those at most 6.5 mm long.

Learn how to estimate the percentage of smaller green ants (at most 6.5 mm) using a histogram. This question involves histogram analysis, frequency distribution, and percentage calculation, ideal for students in Grades 6-8.

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