Math Problem Statement

Okay anyways the relation were given is R=[(x,y): x-y is an even integer ] and asked to find 2 overtime and -3 overline

Solution

Given the relation R={(x,y):xy is an even integer}R = \{(x, y) : x - y \text{ is an even integer} \}, we aim to determine the equivalence classes of 22 (denoted as 2\overline{2}) and 3-3 (denoted as 3\overline{-3}).

Step 1: Understand the equivalence relation

  • A relation RR is an equivalence relation if it is reflexive, symmetric, and transitive. The condition xy is an even integerx - y \text{ is an even integer} satisfies all three properties:
    1. Reflexive: For any xx, xx=0x - x = 0 (even), so (x,x)R(x, x) \in R.
    2. Symmetric: If xyx - y is even, then yxy - x is also even, so (y,x)R(y, x) \in R whenever (x,y)R(x, y) \in R.
    3. Transitive: If xyx - y and yzy - z are even, then xz=(xy)+(yz)x - z = (x - y) + (y - z) is even.

Thus, RR is an equivalence relation.

Step 2: Equivalence classes

The equivalence class of an element aa, denoted a\overline{a}, is defined as: a={yZ:(a,y)R}.\overline{a} = \{y \in \mathbb{Z} : (a, y) \in R\}. For (a,y)R(a, y) \in R, the condition xyx - y is even implies that ay(mod2)a \equiv y \pmod{2}. Hence, all integers in the same equivalence class as aa are congruent to aa modulo 2.

  1. For 2\overline{2}:

    • The equivalence class 2\overline{2} consists of all integers yy such that 2y2 - y is even.
    • This implies y2(mod2)y \equiv 2 \pmod{2}, i.e., yy is an even integer.
    • Therefore, 2={,4,2,0,2,4,6,}\overline{2} = \{ \dots, -4, -2, 0, 2, 4, 6, \dots \}.
  2. For 3\overline{-3}:

    • The equivalence class 3\overline{-3} consists of all integers yy such that 3y-3 - y is even.
    • This implies y3(mod2)y \equiv -3 \pmod{2}, i.e., yy is an odd integer.
    • Therefore, 3={,5,3,1,1,3,5,}\overline{-3} = \{ \dots, -5, -3, -1, 1, 3, 5, \dots \}.

Final Answer:

  • 2={,4,2,0,2,4,6,}\overline{2} = \{ \dots, -4, -2, 0, 2, 4, 6, \dots \} (all even integers).
  • 3={,5,3,1,1,3,5,}\overline{-3} = \{ \dots, -5, -3, -1, 1, 3, 5, \dots \} (all odd integers).

Would you like me to explain equivalence relations further or explore additional examples?


Relative Questions:

  1. What are the key properties of equivalence relations?
  2. How can equivalence classes partition the set of integers?
  3. Can you derive equivalence classes for other values, like 0\overline{0} or 1\overline{1}?
  4. How would this equivalence relation change if the condition was xy is oddx - y \text{ is odd}?
  5. What are some real-world examples of equivalence relations?

Tip:

When determining equivalence classes, focus on identifying a defining property (like congruence modulo nn) that all members share. This often simplifies the problem!

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Math Problem Analysis

Mathematical Concepts

Equivalence Relations
Modulo Arithmetic
Sets and Relations

Formulas

x - y is even <=> x ≡ y (mod 2)
Equivalence Class: \( \overline{a} = \{y \in \mathbb{Z} : (a, y) \in R\} \)

Theorems

Properties of Equivalence Relations (Reflexivity, Symmetry, Transitivity)
Modulo Arithmetic Theorem

Suitable Grade Level

Grades 10-12