Math Problem Statement

Let X \in \mathbb{Q} and x,y \in X, define the equivalence relation x~y \Leftrightarrow x - y is even and an integer. What is th equivalence class?

Solution

Given the equivalence relation xy    xyx \sim y \iff x - y is an even integer, we want to determine the structure of the equivalence classes under this relation.

Step-by-step breakdown:

  1. Set of Rational Numbers: Here, X=QX = \mathbb{Q}, meaning that xx and yy are rational numbers. So x,yQx, y \in \mathbb{Q}.

  2. Equivalence Condition: The condition xy    xyx \sim y \iff x - y is an even integer. We interpret this as follows:

    • For xyx \sim y, the difference xyx - y must be an integer, specifically an even integer. This restricts the relation to certain rational numbers.
  3. Form of the Rational Numbers: Let’s express xx and yy in their general rational form: x=ab,y=cdwhere a,b,c,dZand b,d0.x = \frac{a}{b}, \quad y = \frac{c}{d} \quad \text{where} \ a, b, c, d \in \mathbb{Z} \quad \text{and} \ b, d \neq 0. For xyx - y to be an even integer, we need: abcd=adbcbd\frac{a}{b} - \frac{c}{d} = \frac{ad - bc}{bd} For this to be an even integer, the numerator adbcad - bc must be an even integer, and the denominator bdbd must divide this even integer cleanly, yielding an integer.

  4. Conclusion - Equivalence Class: The equivalence class of any rational number x=abQx = \frac{a}{b} \in \mathbb{Q} under this relation consists of all rational numbers y=cdQy = \frac{c}{d} \in \mathbb{Q} such that: xy is an even integer.x - y \ \text{is an even integer}. In particular, each equivalence class can be described by the congruence of xx and yy modulo 2 when expressed as fractions. This means two rational numbers xx and yy are in the same equivalence class if their difference is even.

The equivalence class of a rational number xQx \in \mathbb{Q} is the set of all rational numbers that differ from xx by an even integer.

Example:

For x=1/2x = 1/2, the equivalence class would be all rational numbers y=cdQy = \frac{c}{d} \in \mathbb{Q} such that 12y\frac{1}{2} - y is an even integer. Thus, one such equivalence class might contain numbers like 12,32,12\frac{1}{2}, \frac{3}{2}, -\frac{1}{2}, etc., since the difference between these numbers and 1/21/2 is an even integer.


Would you like more details on specific equivalence classes or examples?

Related Questions:

  1. How do equivalence relations partition a set?
  2. Can you explain the difference between equivalence classes of rationals vs integers?
  3. How do we find representatives for each equivalence class in general?
  4. What would the equivalence class of 34\frac{3}{4} be under this relation?
  5. Can you provide an example of a non-equivalence relation with similar conditions?

Tip: Equivalence relations divide a set into mutually exclusive equivalence classes, where every element in the set belongs to exactly one class.

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Math Problem Analysis

Mathematical Concepts

Equivalence Relation
Rational Numbers
Modular Arithmetic
Number Theory

Formulas

x ~ y ⇔ x - y is an even integer
x - y = (ad - bc) / bd, where x = a/b, y = c/d and a, b, c, d ∈ ℤ

Theorems

Equivalence Classes
Congruence Modulo

Suitable Grade Level

Undergraduate or advanced high school (Grades 11-12)