Math Problem Statement
Solution
To solve the problem, we'll use the conditions of equilibrium for a particle. A particle is in equilibrium when the vector sum of all forces acting on it is zero. This means that the sum of the forces in the horizontal direction (x-direction) and the vertical direction (y-direction) must each be zero.
Given forces:
- 15 N force directed to the right (horizontal)
- 12 N force directed downward (vertical)
- with unknown magnitude and direction
Let's denote the angle that makes with the horizontal direction as . We can resolve into its horizontal () and vertical () components:
The equilibrium conditions give us two equations:
-
Sum of forces in the x-direction:
-
Sum of forces in the y-direction:
We can solve these equations simultaneously to find the magnitude of and the angle .
First, solve for : Substituting and :
Now, find the angle :
So, the magnitude of is 19.2 N, and the angle it makes with the direction of the 15 N force is approximately 38.7 degrees.
Would you like more details or have any questions?
Here are five related questions for further exploration:
- How would the equilibrium conditions change if the forces were not coplanar?
- What would happen if an additional force was added to the system?
- Can you determine the components of a force if only its magnitude and angle are given?
- How would the system be analyzed if the angle of the force were given instead of the 12 N force?
- How can vector addition be used to find the resultant force in a non-equilibrium situation?
Tip: When dealing with equilibrium problems, always start by resolving all forces into their components and applying the equilibrium conditions to solve for unknowns.
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Math Problem Analysis
Mathematical Concepts
Equilibrium
Vector Resolution
Trigonometry
Formulas
F_x = F \cos \theta
F_y = F \sin \theta
F = \sqrt{(F_x)^2 + (F_y)^2}
tan \theta = \frac{F_y}{F_x}
Theorems
Conditions of Equilibrium
Suitable Grade Level
Grades 10-12
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