Math Problem Statement

The diagram shows an equilateral triangle with side lengths of x cm. The area of the equilateral triangle is 36 cm². Find the value of x, giving your answer correct to 3 significant figures.

Solution

The problem presents an equilateral triangle with side length xx cm and an area of 36 cm². We are tasked with finding the value of xx, correct to 3 significant figures.

Step 1: Formula for the Area of an Equilateral Triangle

The formula for the area AA of an equilateral triangle with side length ss is:

A=s234A = \frac{s^2 \sqrt{3}}{4}

Here, s=xs = x, and the area is given as 36 cm². So, we can set up the equation:

36=x23436 = \frac{x^2 \sqrt{3}}{4}

Step 2: Solve for xx

Multiply both sides of the equation by 4 to eliminate the denominator:

144=x23144 = x^2 \sqrt{3}

Next, divide both sides by 3\sqrt{3}:

x2=1443x^2 = \frac{144}{\sqrt{3}}

To simplify further:

x2=14433x^2 = \frac{144 \sqrt{3}}{3}

x2=483x^2 = 48 \sqrt{3}

Step 3: Compute the Value of xx

Taking the square root of both sides:

x=483x = \sqrt{48 \sqrt{3}}

This value can be computed more accurately with a calculator. Let me compute it for you.The value of xx, correct to 3 significant figures, is 9.129.12 cm.

Would you like further details or have any questions?

Here are 5 related questions to consider:

  1. How is the formula for the area of an equilateral triangle derived?
  2. What other geometric properties can be calculated for an equilateral triangle given its side length?
  3. How would you calculate the height of this triangle?
  4. How can the area formula change for other types of triangles?
  5. Can this method be applied to solve for xx in similar polygons with more sides?

Tip: When solving problems involving square roots, ensure to handle rounding properly to maintain precision at required significant figures.

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Math Problem Analysis

Mathematical Concepts

Geometry
Algebra
Square Roots

Formulas

Area of an equilateral triangle: A = (s^2 * sqrt(3)) / 4

Theorems

Properties of equilateral triangles

Suitable Grade Level

Grades 9-11