Math Problem Statement

Consider the line y = -9/7x+6. Find the equation of the line that is perpendicular to this line and passes through the point (7, - 6). Find the equation of the line that is parallel to this line and passes through the point (7, - 6).

Solution

To find the equations of the lines that are perpendicular and parallel to the given line y=97x+6y = -\frac{9}{7}x + 6, and that pass through the point (7,6)(7, -6), we follow these steps:

1. Equation of the Perpendicular Line

  • Step 1: Determine the slope of the given line. The slope mm of the given line is 97-\frac{9}{7}.

  • Step 2: Determine the slope of the perpendicular line. The slope of a line perpendicular to another is the negative reciprocal of the original line's slope. Therefore, the slope of the perpendicular line is: mperpendicular=79m_{\text{perpendicular}} = \frac{7}{9}

  • Step 3: Use the point-slope form to find the equation of the perpendicular line. The point-slope form of a line is: yy1=m(xx1)y - y_1 = m(x - x_1) where mm is the slope and (x1,y1)(x_1, y_1) is the point the line passes through.

    Substituting m=79m = \frac{7}{9}, x1=7x_1 = 7, and y1=6y_1 = -6: y(6)=79(x7)y - (-6) = \frac{7}{9}(x - 7) Simplifying: y+6=79(x7)y + 6 = \frac{7}{9}(x - 7) y+6=79x499y + 6 = \frac{7}{9}x - \frac{49}{9} y=79x4996y = \frac{7}{9}x - \frac{49}{9} - 6 y=79x499549y = \frac{7}{9}x - \frac{49}{9} - \frac{54}{9} y=79x1039y = \frac{7}{9}x - \frac{103}{9}

    So, the equation of the perpendicular line is: y=79x1039y = \frac{7}{9}x - \frac{103}{9}

2. Equation of the Parallel Line

  • Step 1: Use the same slope as the original line because parallel lines have identical slopes. Therefore, the slope mparallel=97m_{\text{parallel}} = -\frac{9}{7}.

  • Step 2: Use the point-slope form to find the equation of the parallel line. Substituting m=97m = -\frac{9}{7}, x1=7x_1 = 7, and y1=6y_1 = -6: y(6)=97(x7)y - (-6) = -\frac{9}{7}(x - 7) Simplifying: y+6=97(x7)y + 6 = -\frac{9}{7}(x - 7) y+6=97x+637y + 6 = -\frac{9}{7}x + \frac{63}{7} y+6=97x+9y + 6 = -\frac{9}{7}x + 9 y=97x+96y = -\frac{9}{7}x + 9 - 6 y=97x+3y = -\frac{9}{7}x + 3

    So, the equation of the parallel line is: y=97x+3y = -\frac{9}{7}x + 3

Summary:

  • The equation of the line that is perpendicular to y=97x+6y = -\frac{9}{7}x + 6 and passes through (7,6)(7, -6) is y=79x1039y = \frac{7}{9}x - \frac{103}{9}.
  • The equation of the line that is parallel to y=97x+6y = -\frac{9}{7}x + 6 and passes through (7,6)(7, -6) is y=97x+3y = -\frac{9}{7}x + 3.

Do you want more details or have any questions? Here are some related questions you might find interesting:

  1. How can you verify if a point lies on a given line?
  2. What is the significance of the y-intercept in a line's equation?
  3. How do you convert a line equation from point-slope form to slope-intercept form?
  4. What is the general form of a linear equation?
  5. How do you find the distance between a point and a line?

Tip: When finding perpendicular slopes, always remember to take the negative reciprocal of the original slope. This ensures the new line will form a right angle with the original line.

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Math Problem Analysis

Mathematical Concepts

Geometry
Lines
Slope

Formulas

Point-slope form of a line equation
Slope of a line

Theorems

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Suitable Grade Level

Grades 9-12