Math Problem Statement

Consider the line y = -7x+6. Find the equation of the line that is perpendicular to this line and passes through the point (7, - 6). Find the equation of the line that is parallel to this line and passes through the point (7, - 6).

Solution

To find the equations of the lines that are perpendicular and parallel to the given line y=7x+6y = -7x + 6, and that pass through the point (7,6)(7, -6), we follow these steps:

1. Equation of the Perpendicular Line

  • Step 1: Determine the slope of the given line. The given line is in slope-intercept form y=mx+by = mx + b, where mm is the slope. Here, the slope mm of the given line is 7-7.

  • Step 2: Determine the slope of the perpendicular line. The slope of a line perpendicular to another is the negative reciprocal of the original line's slope. Therefore, the slope of the perpendicular line is: mperpendicular=17m_{\text{perpendicular}} = \frac{1}{7}

  • Step 3: Use the point-slope form to find the equation of the perpendicular line. The point-slope form of a line is: yy1=m(xx1)y - y_1 = m(x - x_1) where mm is the slope and (x1,y1)(x_1, y_1) is the point the line passes through.

    Substituting m=17m = \frac{1}{7}, x1=7x_1 = 7, and y1=6y_1 = -6: y(6)=17(x7)y - (-6) = \frac{1}{7}(x - 7) Simplifying: y+6=17(x7)y + 6 = \frac{1}{7}(x - 7) y+6=17x1y + 6 = \frac{1}{7}x - 1 y=17x16y = \frac{1}{7}x - 1 - 6 y=17x7y = \frac{1}{7}x - 7

    So, the equation of the perpendicular line is: y=17x7y = \frac{1}{7}x - 7

2. Equation of the Parallel Line

  • Step 1: Use the same slope as the original line because parallel lines have identical slopes. Therefore, the slope mparallel=7m_{\text{parallel}} = -7.

  • Step 2: Use the point-slope form to find the equation of the parallel line. Substituting m=7m = -7, x1=7x_1 = 7, and y1=6y_1 = -6: y(6)=7(x7)y - (-6) = -7(x - 7) Simplifying: y+6=7x+49y + 6 = -7x + 49 y=7x+496y = -7x + 49 - 6 y=7x+43y = -7x + 43

    So, the equation of the parallel line is: y=7x+43y = -7x + 43

Summary:

  • The equation of the line that is perpendicular to y=7x+6y = -7x + 6 and passes through (7,6)(7, -6) is y=17x7y = \frac{1}{7}x - 7.
  • The equation of the line that is parallel to y=7x+6y = -7x + 6 and passes through (7,6)(7, -6) is y=7x+43y = -7x + 43.

Do you want more details or have any questions? Here are some related questions you might find interesting:

  1. How do you derive the equation of a line given two points?
  2. What is the geometric interpretation of the slope of a line?
  3. How can you determine if two lines are parallel or perpendicular just by looking at their equations?
  4. What happens to the slope when a line is rotated 90 degrees?
  5. How do you find the intersection point of two lines?

Tip: Remember, the slope of a line is a measure of its steepness and direction. Positive slopes rise from left to right, while negative slopes fall from left to right.

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Math Problem Analysis

Mathematical Concepts

Lines
Slope
Perpendicular Lines
Parallel Lines

Formulas

Point-slope form of a line

Theorems

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Suitable Grade Level

Grades 9-12