Math Problem Statement

What is the equation of the trend line in the scatter plot? Use the two yellow points to write the equation in slope-intercept form.

Solution

To solve this, we need to write the equation of the trend line based on the two yellow points shown on the scatter plot. The equation will be in slope-intercept form, y=mx+by = mx + b, where:

  • mm is the slope of the line.
  • bb is the y-intercept.

Step 1: Identify the coordinates of the two yellow points

From the graph:

  • The first yellow point is at (3,2)(3, 2).
  • The second yellow point is at (7,6)(7, 6).

Step 2: Calculate the slope (mm)

The slope formula is: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} Substitute the points (x1,y1)=(3,2)(x_1, y_1) = (3, 2) and (x2,y2)=(7,6)(x_2, y_2) = (7, 6): m=6273=44=1m = \frac{6 - 2}{7 - 3} = \frac{4}{4} = 1

So, the slope m=1m = 1.

Step 3: Find the y-intercept (bb)

Using the slope-intercept form y=mx+by = mx + b, substitute m=1m = 1 and one of the points, such as (3,2)(3, 2): 2=1(3)+b2 = 1(3) + b 2=3+b2 = 3 + b b=23=1b = 2 - 3 = -1

Step 4: Write the equation

The equation of the line is: y=1x1or simplyy=x1y = 1x - 1 \quad \text{or simply} \quad y = x - 1

Final Answer:

The equation of the trend line is: y=x1y = x - 1

Would you like more clarification, or do you have further questions? Here are 5 follow-up questions to consider:

  1. What does the slope of the line represent in this context?
  2. How would the equation change if the points were different?
  3. What are some real-world applications of finding trend lines in scatter plots?
  4. How can we confirm that the trend line fits the data well?
  5. Can you describe how to calculate the y-intercept when given only the slope and one point?

Tip: Always double-check your calculations by substituting both points into your final equation to verify correctness!

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Math Problem Analysis

Mathematical Concepts

Algebra
Coordinate Geometry
Trend Lines

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)
Slope-intercept form: y = mx + b

Theorems

Linear Equation

Suitable Grade Level

Grades 8-10