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The question is asking to find the equation of a line that passes through the point \( (8, -1) \) and is perpendicular to a line with a slope of \( \frac{7}{13} \).

### Steps to solve:

1. **Perpendicular Slope**: 
   The slope of a line perpendicular to another is the negative reciprocal of the original slope. 
   - Given slope = \( \frac{7}{13} \), the perpendicular slope is \( -\frac{13}{7} \).

2. **Point-Slope Form**:
   To find the equation of the line, use the point-slope form of a line equation:
   \[
   y - y_1 = m(x - x_1)
   \]
   where \( m \) is the slope and \( (x_1, y_1) \) is the point the line passes through.

3. **Substitute Values**:
   - \( m = -\frac{13}{7} \)
   - \( (x_1, y_1) = (8, -1) \)

   Substituting these into the point-slope form:
   \[
   y - (-1) = -\frac{13}{7}(x - 8)
   \]
   Simplify:
   \[
   y + 1 = -\frac{13}{7}(x - 8)
   \]
  

Find the equation of the line through the point (8, -1) that is perpendicular to the line with slope 7/13.

Learn how to find the equation of a line passing through the point (8, -1) that is perpendicular to a line with slope 7/13. This problem involves the point-slope form and the concept of negative reciprocal slopes for perpendicular lines, suitable for high school students in Grades 9-12.

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