A line contains the point (3, 0) and has a slope of -1.

Which is the equation of the line?

Responses

y=−x−3
y is equal to negative x minus 3

y=−x+3
y is equal to negative x plus 3

y=x−3
y is equal to x minus 3

y=x+3

To find the equation of a line with a given point and slope, you can use the point-slope form of a line, which is:

\[
y - y_1 = m(x - x_1)
\]

where \((x_1, y_1)\) is the point on the line and \(m\) is the slope.

Given the point \((3, 0)\) and a slope of \(-1\):

1. Substitute the values into the formula:
   \[
   y - 0 = -1(x - 3)
   \]
2. Simplify:
   \[
   y = -1(x - 3) \\
   y = -x + 3
   \]

Thus, the equation of the line is:

\[
y = -x + 3
\]

So the correct response is:

**y = -x + 3**

If you have any questions or need further details, feel free to ask! Here are some related questions you might consider:

1. How do you convert this equation to slope-intercept form?
2. What is the y-intercept of this line?
3. How would you graph this line?
4. What would the equation of a line with a slope of 1 through the same point be?
5. How do you determine if two lines are parallel or perpendicular?

**Tip:** Always ensure to plot the point and use the slope to find another point when graphing a line!

A line contains the point (3, 0) and has a slope of -1. Which is the equation of the line?

Explore how to determine the equation of a line passing through the point (3, 0) with a slope of -1. This problem illustrates the use of the point-slope form of a linear equation. Suitable for students in Grades 7-9.

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