To find the equation of a line with a given slope $m = 3$ and passing through the point $(-2, -1)$, we can use the point-slope form of a line equation:

$y - y_1 = m(x - x_1)$

where:

• $m = 3$ (the slope),
• $(x_1, y_1) = (-2, -1)$ (the point it passes through).

Substitute the values into the equation:

$y - (-1) = 3(x - (-2))$

Simplify:

$y + 1 = 3(x + 2)$

Now expand the right-hand side:

$y + 1 = 3x + 6$

Subtract 1 from both sides to solve for $y$:

$y = 3x + 5$

So, the equation of the line in slope-intercept form is:

$y = 3x + 5$

Alternatively, you can express it in general form by moving all terms to one side:

$3x - y = -5$

Would you like further details or have any questions?

Here are some related questions:

1. How do you convert between point-slope and slope-intercept forms of a line?
2. What is the general form of a linear equation?
3. How do you determine the slope of a line from two points?
4. What are the steps to graph a line given its equation?
5. How do you find the x- and y-intercepts of a line?

Tip: Always check if you can simplify or rearrange your final equation to suit the form requested (slope-intercept or general form).