line f is 6x+y=7. perpendicular to line f is like f which passes through (-10,-1) what’s the equation of g? no explainatuon just wndeer

The equation of line \( g \), which is perpendicular to line \( f: 6x + y = 7 \) and passes through the point \( (-10, -1) \), is:

\[
g: y = \frac{1}{6}x + \frac{7}{3}
\]

Do you want details or have any questions?

Here are 5 related questions:

1. How do you find the slope of a perpendicular line?
2. Can you derive the equation of a line given a point and a slope?
3. How do you convert a linear equation from standard form to slope-intercept form?
4. How does the slope of a perpendicular line relate to the original line's slope?
5. How would you graph two perpendicular lines?

**Tip:** Perpendicular lines have slopes that are negative reciprocals of each other.

line f is 6x+y=7. perpendicular to line f is like f which passes through (-10,-1) what’s the equation of g?

Learn how to find the equation of a line that is perpendicular to 6x + y = 7 and passes through the point (-10, -1). This problem uses the slope formula, equation of a line, and the concept of perpendicular slopes. Suitable for high school students in Grades 9-12.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation