Math Problem Statement

Lines BG and CF never cross or intersect. What is the equation for line CF? Show your work or explain your reasoning. (5)

Solution

Let's go through the questions in the diagram one by one. I will explain the reasoning and solutions.

Question 3.1:

Lines BG and CF never cross or intersect. What is the equation for line CF?

  • From the diagram, we can observe that line CFCF is parallel to line BGBG.
  • The equation for line BGBG is already given as y=2x+4y = 2x + 4. Since CFCF is parallel to BGBG, the slope of CFCF must also be the same as BGBG, i.e., slope m=2m = 2.
  • To find the equation of line CFCF, we need to find the y-intercept, denoted as cc.
  • Point FF lies on line CFCF and has coordinates F(x,y)=(6,7)F(x, y) = (6, 7) based on the grid.

Using the point-slope form: yy1=m(xx1)y - y_1 = m(x - x_1) Substitute m=2m = 2, x1=6x_1 = 6, and y1=7y_1 = 7: y7=2(x6)y - 7 = 2(x - 6) y7=2x12y - 7 = 2x - 12 y=2x12+7y = 2x - 12 + 7 y=2x5y = 2x - 5 Thus, the equation of line CFCF is y=2x5\boxed{y = 2x - 5}.


Question 3.2:

What is the size of angle HIG?

  • From the diagram, we can observe that HIGHIG is a straight angle (a line through points H,I,GH, I, G), and a straight line forms an angle of 180180^\circ. Thus, the size of angle HIGHIG is 180\boxed{180^\circ}.

Question 3.3:

What is the size of angle DLE?

  • From the diagram, angle DLEDLE and angle MLFMLF form a linear pair (supplementary angles), and the sum of supplementary angles is 180180^\circ.
  • We are given that MLF=137\angle MLF = 137^\circ. Thus: DLE=180137=43\angle DLE = 180^\circ - 137^\circ = 43^\circ So, the size of angle DLEDLE is 43\boxed{43^\circ}.

Question 3.4:

How does the size of angle IJK relate to the size of angle MKL?

  • From the diagram, it appears that lines IJIJ and KLKL are intersected by line JKJK, forming a pair of alternate interior angles.
  • Since alternate interior angles are congruent when lines are parallel, the size of angle IJKIJK is equal to the size of angle MKLMKL. Thus: IJK=MKL\angle IJK = \boxed{\angle MKL}

Question 3.5:

If MK = 3 meters and KL = 4 meters, then how long is LM?

  • From the diagram, we can see that triangle MKLMKL forms a right triangle.
  • By applying the Pythagorean Theorem: LM2=MK2+KL2LM^2 = MK^2 + KL^2 LM2=32+42=9+16=25LM^2 = 3^2 + 4^2 = 9 + 16 = 25 LM=25=5metersLM = \sqrt{25} = 5 \, \text{meters} Thus, the length of LMLM is 5meters\boxed{5} \, \text{meters}.

Question 3.6:

What is the sum of angle MIJ plus angle IJK plus angle KLM?

  • MIJ\angle MIJ, IJK\angle IJK, and KLM\angle KLM are the angles around point JJ and along a straight line, so the sum of these angles should equal 180180^\circ. Thus: 180\boxed{180^\circ}

Would you like more details on any of the steps, or do you have any further questions?

5 Related Questions:

  1. How do we calculate the equation of a line if it passes through two given points?
  2. What is the general form of the equation of a straight line?
  3. Can you explain how to determine congruent angles in different types of geometrical figures?
  4. How does the Pythagorean Theorem help in solving distances in geometry?
  5. What are supplementary angles, and how are they related to linear pairs?

Tip:

When working with parallel lines and transversals, always look for corresponding and alternate angles, as they are congruent, making many problems easier to solve.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Parallel Lines
Angles
Pythagorean Theorem

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)
Point-slope form: y - y1 = m(x - x1)
Pythagorean theorem: a^2 + b^2 = c^2

Theorems

Linear Pair Theorem
Alternate Interior Angles Theorem

Suitable Grade Level

Grades 9-11