Math Problem Statement

Write an equation for the function graphed above.

Solution

The graph shows a function with a vertical asymptote at x=1x = -1 and a rapid increase to positive and negative infinity near this asymptote, which suggests the presence of a logarithmic function shifted horizontally. Given these characteristics, a likely candidate is a logarithmic function of the form:

y=ln(x+1)y = \ln(x + 1)

This function has the following properties:

  • A vertical asymptote at x=1x = -1.
  • It rapidly approaches negative infinity as xx approaches 1-1 from the right.
  • It grows slowly after x=1x = -1, similar to the graph.

Therefore, the equation of the function graphed above is:

y=ln(x+1)y = \ln(x + 1)

Would you like more details on this solution, or do you have any questions?

Here are some related questions you might find interesting:

  1. How do you determine the vertical asymptote of a logarithmic function?
  2. What transformations can be applied to logarithmic functions to shift their graphs?
  3. How do you find the domain of a logarithmic function?
  4. What are the characteristics of exponential and logarithmic graphs?
  5. How do you determine the equation of a graph with an asymptote?

Tip: For identifying logarithmic functions, always look for key features like vertical asymptotes and slow growth rates after certain points on the x-axis.

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Math Problem Analysis

Mathematical Concepts

Logarithmic Functions
Asymptotes

Formulas

y = ln(x + 1)

Theorems

Properties of Logarithmic Functions

Suitable Grade Level

Grades 10-12