(12*(295804kg/cm2)*(24850489cm4)*1.5m)/(12.48m+6.83m)3

Let's break down the given expression step by step:

The expression is:

\[
\frac{12 \times (295804 \, \text{kg/cm}^2) \times (24850489 \, \text{cm}^4) \times (1.5 \, \text{m})}{(12.48 \, \text{m} + 6.83 \, \text{m})^3}
\]

We can compute this in stages:

### Step 1: Multiplication of the numerator
Multiply the values in the numerator:

\[
12 \times 295804 \, \text{kg/cm}^2 \times 24850489 \, \text{cm}^4 \times 1.5 \, \text{m}
\]

### Step 2: Sum and cubing of the denominator
Add the terms in the denominator and then raise it to the power of 3:

\[
(12.48 \, \text{m} + 6.83 \, \text{m})^3
\]

Finally, divide the result of Step 1 by the result of Step 2.

Let me compute that for you.The result of the expression is approximately:

\[
1.837 \times 10^{10} \, \text{(or)} \, 18,376,578,971.48
\]

This is the final value after performing the multiplication and division.

Would you like further details on any step? Here are 5 related questions for practice:

1. How do you handle units when multiplying or dividing physical quantities?
2. What is the significance of cubing the sum in the denominator?
3. How can dimensional analysis be used to ensure the correctness of the result?
4. How would the result change if the power in the denominator was different?
5. Can this formula be related to any engineering principles like stress or bending moments?

**Tip:** Always check the units at every step when solving physics-related equations to avoid dimensional inconsistencies.

(12*(295804kg/cm2)*(24850489cm4)*1.5m)/(12.48m+6.83m)^3

Explore how to solve a complex engineering problem involving multiplication and division of quantities with units such as kg/cm², cm⁴, and meters. This example includes unit conversion and cubing the sum of terms in the denominator. Suitable for university-level engineering and physics students.

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