Math Problem Statement
Solution
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Part (i): Determine the transition level of the electron which emitted a photon with a wavelength of 1280 nm in the Paschen series.
Solution: The Paschen series corresponds to transitions where the final energy level (n₂) is 3. The wavelength of the photon can be related to the energy difference between two energy levels using the Rydberg formula for hydrogen:
where:
- is the wavelength (1280 nm),
- is the Rydberg constant (),
- for the Paschen series (final state),
- is the initial energy level (to be determined).
Rewriting the formula to solve for , we get:
We will substitute the values and solve for .
Part (ii): Calculate the energy change for the formation of the line with the lowest energy in the Paschen series.
Solution: The lowest energy line in the Paschen series corresponds to the transition from to . The energy difference is given by the formula:
where:
- is Planck’s constant (),
- is the speed of light (),
- and .
We will calculate this energy in joules.
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Here are some related questions for practice:
- What is the significance of the Rydberg constant in atomic physics?
- How does the Paschen series differ from the Balmer and Lyman series in terms of electron transitions?
- What factors influence the energy change during electron transitions in hydrogen atoms?
- How can we derive the energy of a photon from its wavelength?
- Why does
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Math Problem Analysis
Mathematical Concepts
Rydberg Formula
Photon Energy
Electron Transitions
Formulas
1/λ = R_H * (1/n_2^2 - 1/n_1^2)
E = h * c * (1/n_2^2 - 1/n_1^2)
Theorems
Rydberg Constant
Energy of a Photon
Suitable Grade Level
College-level physics or high school advanced physics
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