Math Problem Statement

Escolha a alternativa que seja o cálculo correto da integral dupla: ∫₄⁷∫π²π r dr dθ

Solution

The given problem asks to compute the double integral:

47π2πrdθdr\int_{4}^{7} \int_{\pi}^{2\pi} r \, d\theta \, dr

This is a double integral in polar coordinates where the integrand is rr. The integral is split into two parts, with limits for rr ranging from 4 to 7 and θ\theta ranging from π\pi to 2π2\pi.

Step-by-step solution:

  1. Inner Integral: The inner integral is with respect to θ\theta, treating rr as a constant: π2πrdθ=r[θ]π2π=r(2ππ)=rπ\int_{\pi}^{2\pi} r \, d\theta = r \left[ \theta \right]_{\pi}^{2\pi} = r \cdot (2\pi - \pi) = r \cdot \pi So, the result of the inner integral is rπr\pi.

  2. Outer Integral: Now, integrate the result rπr\pi with respect to rr: 47rπdr=π47rdr=π[r22]47\int_{4}^{7} r\pi \, dr = \pi \int_{4}^{7} r \, dr = \pi \left[ \frac{r^2}{2} \right]_{4}^{7} =π(722422)=π(492162)= \pi \left( \frac{7^2}{2} - \frac{4^2}{2} \right) = \pi \left( \frac{49}{2} - \frac{16}{2} \right) =π(332)=33π2= \pi \left( \frac{33}{2} \right) = \frac{33\pi}{2}

Final Answer:

The value of the double integral is 33π2\frac{33\pi}{2}.

Would you like further details or have any questions? Here are some related questions to extend your understanding:

  1. How do you change a Cartesian integral into a polar form?
  2. What are the applications of double integrals in polar coordinates?
  3. How would the limits change if the problem was set in Cartesian coordinates?
  4. What is the geometric interpretation of this double integral?
  5. How would the result differ if the limits for θ\theta were from 0 to π\pi?

Tip: Always check the order of integration and ensure that each variable is integrated within its correct limits!

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Math Problem Analysis

Mathematical Concepts

Double Integral
Polar Coordinates
Integral Calculus

Formulas

∫∫ r dr dθ
∫ f(r, θ) dr dθ

Theorems

Fundamental Theorem of Calculus
Properties of Definite Integrals

Suitable Grade Level

University Level