Math Problem Statement
Solution
To evaluate the given double integral, let's go through the problem step-by-step.
The integral is written in polar coordinates as:
The function is multiplied by due to the Jacobian determinant when converting to polar coordinates.
Step 1: Simplify the Integrand
The integrand becomes:
Thus, the integral can be rewritten as:
Step 2: Integrate with Respect to
Now, we focus on the inner integral with respect to :
Since is independent of , we can factor it out:
Evaluate the inner integral:
Thus, the integral becomes:
Step 3: Integrate with Respect to
Now, evaluate the remaining integral:
The integral of is :
Final Answer
Since this last integral evaluates to zero, the value of the entire double integral is:
Region
The region in polar coordinates is defined by:
- ranging from 0 to 5 (a radius up to 5 units)
- ranging from 0 to (a half-circle in the first and second quadrants)
So, represents the upper half of a disk with radius 5.
Would you like a more detailed breakdown of any part of this solution, or do you have questions about the region sketch?
Related Questions:
- What is the significance of using polar coordinates in double integrals?
- How would the integral change if the limits for were from to ?
- What is the purpose of the Jacobian in coordinate transformations?
- How do we determine the appropriate region in polar coordinates?
- Can we convert any double integral from Cartesian to polar coordinates?
Tip: When integrating in polar coordinates, always remember to include in the integrand to account for the area element .
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Math Problem Analysis
Mathematical Concepts
Double Integration
Polar Coordinates
Jacobian Determinant
Area of a Region
Formulas
Double integral in polar coordinates: ∫∫_R f(r, θ) dA = ∫_a^b ∫_c^d f(r, θ) r dr dθ
Integration of r^2 and cos(θ) terms
Theorems
Jacobian determinant for polar coordinates
Suitable Grade Level
Undergraduate Calculus
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