Math Problem Statement
Solution
To solve this problem, let’s analyze the requirements:
- Total Cookies: We have 10 cookies in total.
- Jars: There are 5 jars labeled and .
- Objective: Distribute the cookies so that exactly 2 jars contain exactly 2 cookies each.
Step 1: Define the Variables
Let’s denote the number of cookies in each jar as and , where: and for all jars.
Step 2: Specify Conditions for Exactly 2 Jars with 2 Cookies
We want exactly 2 jars to contain exactly 2 cookies each, meaning:
- Two of these 's should be equal to 2.
- The other three should add up to .
Step 3: Select 2 Jars to Have 2 Cookies
The number of ways to choose 2 jars out of 5 to contain exactly 2 cookies is given by the combination:
Step 4: Distribute Remaining 6 Cookies Among 3 Jars
We now have three jars that must contain the remaining 6 cookies. The jars can have any non-negative number of cookies, meaning we are looking for the number of non-negative integer solutions to: This is a classic "stars and bars" problem, where the number of non-negative integer solutions is given by:
Step 5: Calculate the Total Number of Distributions
Since there are 10 ways to select the jars that will contain exactly 2 cookies each, and 28 ways to distribute the remaining 6 cookies among the other three jars, we multiply these values:
Final Answer
There are 280 ways to distribute the 10 cookies in 5 jars so that exactly 2 jars contain exactly 2 cookies.
Would you like more details or have any questions?
Here are 5 related questions that build on this problem:
- How would the solution change if we wanted exactly 3 jars to contain exactly 2 cookies?
- What if each jar must contain at least 1 cookie? How would that affect the number of ways?
- Can this method be generalized for different numbers of cookies or jars?
- How would the solution be affected if we wanted at least two jars to contain at least one cookie each?
- How does the stars and bars method apply when additional restrictions are added?
Tip: For combinatorial problems involving distributions with conditions, breaking down the conditions and using combinations with the "stars and bars" method simplifies the solution process.
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Math Problem Analysis
Mathematical Concepts
Combinatorics
Stars and Bars Method
Combinations
Formulas
Combination formula: \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)
Stars and Bars formula for non-negative integer solutions: \( \binom{n + r - 1}{r - 1} \)
Theorems
Combination theorem
Stars and Bars theorem
Suitable Grade Level
Grades 9-12
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