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To solve this problem, let’s analyze the requirements:

1. **Total Cookies**: We have 10 cookies in total.
2. **Jars**: There are 5 jars labeled \( A, B, C, D, \) and \( E \).
3. **Objective**: Distribute the cookies so that exactly 2 jars contain exactly 2 cookies each.

### Step 1: Define the Variables
Let’s denote the number of cookies in each jar as \( x_A, x_B, x_C, x_D, \) and \( x_E \), where:
\[
x_A + x_B + x_C + x_D + x_E = 10
\]
and \( x_i \geq 0 \) for all jars.

### Step 2: Specify Conditions for Exactly 2 Jars with 2 Cookies
We want exactly 2 jars to contain exactly 2 cookies each, meaning:
- Two of these \( x_i \)'s should be equal to 2.
- The other three should add up to \( 10 - 4 = 6 \).

### Step 3: Select 2 Jars to Have 2 Cookies
The number of ways to choose 2 jars out of 5 to contain exactly 2 cookies is given by the combination:
\[
\binom{5}{2} = 10
\]

### Step 4: Distribute Remaining 6 Cookies Among 3 Jars
We now have three jars that must contain the remaining 6 cookies. The jars can have any non-negative number of cookies, meaning we are looking for the number of non-negative integer solutions to:
\[
x_1 + x_2 + x_3 = 6
\]
This is a classic "stars and bars" problem, where the number of non-negative integer solutions is given by:
\[
\binom{6 + 3 - 1}{3 - 1} = \binom{8}{2} = 28
\]

### Step 5: Calculate the Total Number of Distributions
Since there are 10 ways to select the jars that will contain exactly 2 cookies each, and 28 ways to distribute the remaining 6 cookies among the other three jars, we multiply these values:
\[
10 \times 28 = 280
\]

### Final Answer
There are **280 ways** to distribute the 10 cookies in 5 jars so that exactly 2 jars contain exactly 2 cookies.

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Would you like more details or have any questions?

Here are 5 related questions that build on this problem:
1. How would the solution change if we wanted exactly 3 jars to contain exactly 2 cookies?
2. What if each jar must contain at least 1 cookie? How would that affect the number of ways?
3. Can this method be generalized for different numbers of cookies or jars?
4. How would the solution be affected if we wanted at least two jars to contain at least one cookie each?
5. How does the stars and bars method apply when additional restrictions are added?

**Tip**: For combinatorial problems involving distributions with conditions, breaking down the conditions and using combinations with the "stars and bars" method simplifies the solution process.

10 Cookies have to be kept in 5 jars A, B, C, D, E. A jar may contain any number of cookies (including 0). What is the number of ways to distribute so that exactly 2 jars contain exactly 2 cookies?

Explore the combinatorial approach to distributing 10 cookies into 5 jars so that exactly 2 jars contain exactly 2 cookies. This solution covers key concepts like combinations and the stars and bars method, suitable for students in Grades 9-12.

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