Math Problem Statement
Solution
The problem in the image asks to find the distance from point to the line in a cube with a side length of 8 cm.
Step-by-step Solution:
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Identify the position of point :
In the diagram, point is the midpoint of the top edge of the cube. Since the cube has a side length of 8 cm, the position of relative to the other vertices can be determined. -
Coordinates of key points:
Let's set the origin at point with the following coordinates:- Point is the midpoint of , so its coordinates are:
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Distance from point to line :
The line lies on the plane and is a vertical line between and . The direction vector of this line is:To find the perpendicular distance from point to the line , we use the formula for the distance between a point and a line in 3D space: where .
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Calculating the cross product :
\begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ -4 & 0 & 8 \\ -8 & 0 & 0 \end{vmatrix} = \hat{i}(0 - 0) - \hat{j}(-32 - 0) + \hat{k}(0 - 0) = 32\hat{j}$$ So, $$\overrightarrow{CS} \times \overrightarrow{CD} = (0, 32, 0)$$. -
Magnitude of the cross product:
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Magnitude of the direction vector :
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Final distance:
Thus, the distance from point to line is 4 cm.
Would you like more details on any of the steps or have additional questions?
Here are five related questions for further practice:
- How would you find the distance from point to line ?
- What is the distance from point to line ?
- How can you calculate the distance between two skew lines in 3D?
- What is the length of the diagonal of the cube?
- How do you find the angle between two lines in 3D?
Tip: When dealing with cubes, try to set up a coordinate system to simplify the calculation of distances and vectors.
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Math Problem Analysis
Mathematical Concepts
Geometry
Distance in 3D Space
Vector Calculations
Formulas
Distance between a point and a line in 3D space
Cross product of vectors
Magnitude of a vector
Theorems
Distance Formula in 3D Geometry
Properties of Vectors and Cross Product
Suitable Grade Level
Grades 10-12
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