Math Problem Statement

What is the distance, rounded to the nearest tenth, between the points (2, -2) and (6, 3)?

Solution

To calculate the distance between the two points (2,2)(2, -2) and (6,3)(6, 3), we use the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step-by-step solution:

  1. Assign the coordinates:

    • x1=2,y1=2x_1 = 2, y_1 = -2
    • x2=6,y2=3x_2 = 6, y_2 = 3
  2. Substitute these values into the formula: d=(62)2+(3(2))2d = \sqrt{(6 - 2)^2 + (3 - (-2))^2}

  3. Simplify inside the parentheses: d=(4)2+(5)2d = \sqrt{(4)^2 + (5)^2}

  4. Square the terms: d=16+25d = \sqrt{16 + 25}

  5. Add the squares: d=41d = \sqrt{41}

  6. Take the square root and round to the nearest tenth: d6.4 units.d \approx 6.4 \text{ units.}

Final Answer:

6.4units\boxed{6.4 \, \text{units}}

Would you like further clarification or more details on the process?


Here are 5 related questions for practice:

  1. How do you derive the distance formula from the Pythagorean theorem?
  2. What is the distance between (3,4)(-3, 4) and (7,2)(7, -2)?
  3. How do you find the midpoint of two points?
  4. How is the distance formula applied in 3D space?
  5. What is the shortest distance between a point and a line?

Tip: When solving distance problems, double-check your signs when subtracting coordinates, as errors often occur there.

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Math Problem Analysis

Mathematical Concepts

Geometry
Coordinate Systems

Formulas

Distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10